(x^2)+1x+19=0

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Solution for (x^2)+1x+19=0 equation:


Simplifying
(x2) + 1x + 19 = 0
x2 + 1x + 19 = 0

Reorder the terms:
19 + 1x + x2 = 0

Solving
19 + 1x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + 1x + -19 + x2 = 0 + -19

Reorder the terms:
19 + -19 + 1x + x2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + 1x + x2 = 0 + -19
1x + x2 = 0 + -19

Combine like terms: 0 + -19 = -19
1x + x2 = -19

The x term is 1x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -19 + 0.25

Reorder the terms:
0.25 + x + x2 = -19 + 0.25

Combine like terms: -19 + 0.25 = -18.75
0.25 + x + x2 = -18.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -18.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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